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LO82   SQ1 The Peak integration Give H =1+2+3+(6+1)+9 =22 It has O=5 and 2 un-saturation so CnH(2n-2)O5 So calculating n we get n=12 so the molecular formula is C12H22O5 Now The molecule show 2 tautomeric forms since it involve oxygen So it would be Keto enol tautomer. Further the molecule Has Most of the H atom in Upfield So ((6+1)+ 9))=16 H atom in